If the diagonal of a parallelogram …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Rohit Jadhav 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
Given : A parallelogram ABCD , in which AC = BD
TO Prove : ABCD is a rectangle .
Proof : In △ABC and △ABD
AB = AB [common]
AC = BD [given]
BC = AD [opp . sides of a | | gm]
⇒ △ABC ≅ △BAD [ by SSS congruence axiom]
⇒ ∠ABC = △BAD [c.p.c.t.]
Also, ∠ABC + ∠BAD = 180° [co - interior angles]
⇒ ∠ABC + ∠ABC = 180° [∵ ∠ABC = ∠BAD]
⇒ 2∠ABC = 180°
⇒ ∠ABC = 1 /2 × 180° = 90°
Hence, parallelogram ABCD is a rectangle.
Related Questions
Posted by Savitha Savitha 1 year, 4 months ago
- 0 answers
Posted by Sheikh Alfaz 1 month, 2 weeks ago
- 0 answers
Posted by Akhilesh Patidar 1 year, 4 months ago
- 0 answers
Posted by Duruvan Sivan 6 months, 1 week ago
- 0 answers
Posted by Alvin Thomas 3 months ago
- 0 answers
Posted by Yash Pandey 6 months, 1 week ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sunita Sah 5 years, 4 months ago
1Thank You