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Find the zeros of x2-2x-8

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Find the zeros of x2-2x-8
  • 4 answers

Amrita Kumari 5 years, 3 months ago

x2 - 2x - 8 =x2 - (4 - 2)x - 8 =x2 - 4x + 2x - 8 =x(x - 4) + 2(x - 4) =(x - 4)(x + 2)=0 (x - 4)=0 or (x + 2)=0 x=4 x = -2 So zeros are 4 and -2

Sushmita Singh 5 years, 3 months ago

x2-2x-8 = x2 - 4x + 2x - 8 = x( x - 4) + 2 (x - 4) = ( x + 2) ( x - 4)

Swadha Sinha 5 years, 3 months ago

x2 - 2x - 8 = 0 = x2 - 4x + 2x - 8 = 0 = x(x - 4) + 2(x - 4) = 0 = (x + 2) (x - 4) = 0 So zeros are -2 and 4

Yogita Ingle 5 years, 3 months ago

x2-2x-8
= x2 - 4x + 2x - 8

= x( x - 4) + 2 (x - 4)
= ( x + 2) ( x - 4)

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