A quadrilateral ABCD is drawn to …

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Gaurav Seth 5 years, 3 months ago
Since, tangents drawn from an exterior point to a circle are equal in length.

∴ AP = AS ...(i)
BP = BQ ...(ii)
CR = CQ ...(iii)
and DR = DS ...(iv)
Adding (i), (ii), (iii) and (iv), we get
AP + BP + CR + DR = AS + BQ + CQ + DS
⇒ (AP + BP) + (CR + DR)
= (AS + DS) + (BQ + CQ)
⇒ AB + CD = AD + BC
Hence, AB + CD = BC + DA.
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