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1^537 +i^539 + i^541 /i^534+ i^536+i^538 …

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1^537 +i^539 + i^541 /i^534+ i^536+i^538 =

    • Posted by Athmapriya P 4 years, 7 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Gargi Aggarwal 4 years, 7 months ago

    i^537+i^539+i^541 =i.i^536+i.i^538+i.i^540 =i.(i^2)^268+i.(i^2)^269+i.(i^2)^270 =i.1+i.(-1)+i.1 [because (i^2)^even no.=1 and (i^2)^odd no.=-1] =i-i+i =i

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