A body covers 12m in 2nd …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Vanshika Xxxx 4 years, 8 months ago
- 2 answers
Yogita Ingle 4 years, 8 months ago
Case I:
let initial velocity = u m/s
distance=s=12m
Time =t=2sec
S=u+a(2t-1)/2
12=u+(2x2-1)/2
12=u+3a/2
2u+3a=24--------------(1)
Case II:
Time=t=4sec
distance =s=20m
20=u+a(2x4-1)/2
20=u+7a/2
2u+7a=40--------(2)
from 1 and 2:
2u+3a=24
2u+7a=40
- - -
***********
-4a=-16
a=4m/s2
substitute the value of a in equation 1 we get :
u=6m/s
Case iii:
Now, distance covered in 4sec after 5second=distance covered in 9th sec-distance covered in 5 sec
=(6x9+1/24x9x9)-(6x5+1/2*4*5*5)
=54+162-(30+50)
=136m
Related Questions
Posted by Nekita Baraily 9 months ago
- 2 answers
Posted by Mohammed Javith 9 months, 1 week ago
- 0 answers
Posted by M D 9 months ago
- 1 answers
Posted by Pankaj Tripathi 9 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Vanshika Xxxx 4 years, 8 months ago
0Thank You