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Area of a triangle, two sides of which 8cmand 11cm and perimeter is 32 cm

Posted by Payal Ranjan 4 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 2 months ago

Perimeter = 32 cm, a = 8 cm, b = 11 cm
Perimeter = a + b + c

32 = 8 + 11 + c
32 = 19 + c
c = 32 - 19 = 13
S= 32/2 = 16 cm

Area of triangle = √s(s- a) ( s - b) (s-c)

= √ 16 (16 - 8) (16 -11) (16-13)
= √16 (8) (5) (3) cm²

Area of triangle = 8√30 cm²

1Thank You

ANSWER

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