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(v) (k - 12) x2 + …

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(v) (k - 12) x2 + 2 (k - 12) x ·+ 2 = 0 . ( vz) x2 - 4kx + k = 0

Posted by Abhay Singh 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

Here, a = k – 12, b = 2 (k – 12), c = 2
∴ D = b² – 4ac = [2(k– 12)]²
– 4(k – 12) x 2
= 4 (k – 12)²– 8 (k– 12)
Roots are equal, if D = 0
⇒ 4 (k – 12) 2 – 8 (k – 12) = 0
⇒ 4(k – 12)(k – 12 – 2) = 0
⇒ (k – 12) (k – 14) = 0
⇒ k = 12 or 14
But k = 12 does not satisfy the eqn.
k = 14 Ans.

0Thank You

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CBSE > Class 10 > Mathematics