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t²-15 Que. From polynomials

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t²-15 Que. From polynomials

    • Posted by Jithu 11 4 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Aastha Barbate 4 years, 10 months ago

    By comparing the given poly. with ax^2 + bx + c =0,we get a = 1, b=0, c=-15 We have, t^2-15=0 t=+_√15 Therefore, the zeroes of the polynomial t^2-√15 are √15,-√15 Now, sum of zeroes=-b/a √15 - √15= -0/1 0=0 Also, product of zeroes=c/a √15 × (-√15) = 15/1 15 = 15 Hence, Verified

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