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Find the zeroes of the polynomial …

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Find the zeroes of the polynomial 100x^2-81
  • 2 answers

Gargi Nawghade 4 years, 10 months ago

100x²-81 = 0 => 100x² = 81 => x² = 81/100 => x = +/- _/81/100 => x= +/- 9/10 So, the zeroes are 9/10 , -9/10

Aditya Vavhal 4 years, 10 months ago

It can be solve by factorzation method
http://mycbseguide.com/examin8/

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