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Find the area of a quadarant …

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Find the area of a quadarant of a Circle whose circumference 22cm

Posted by Manjula Desai 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Vignesh Babu 5 years, 3 months ago

????????????? = ???? ?π? = ?? 2 x 22/7 x r = 22 r = 22 x 7/2 x 22 ? = ?/? In quadrant, angle of sector, = 90° Area of the quadrant = 90°/360° × πr^2 = 40 × 22/7 × 7/2 × 7/2 = 1540 cm^2 ᎻᎾᏢᎬ ᎷᎽ ᎯᏁᏕᏯᎬᏒ ᏯᎨᏝᏝ ᏰᎬ ᎻᎬᏝᏢƒυℓℓ

Muskan Kumari 5 years, 3 months ago

Circumference= 2×22/7×r 22=2×22/7×r r=22×7/2×22 r=7/2=3.5 cm Area of quadrant= 1/4×22/7×7/2×7/2 =77/8cm²

Gaurav Seth 5 years, 3 months ago

Formulas used =
1. Circumference = 2 pie r
2. Area of Quadrant = 1/4 Pie r²

Circumference = 2 Pie r
22 = 2 * 22/7 r
r = 22 * 7 / 22 * 2
r = 7/2 or 3.5 cm

Area Of Quadrant = 1/4 Pie r²
= (1/4) * (22/7 ) * 3.5 * 3.5
= 1 * 22 * 35 * 35 / 4 * 7 * 10 * 10
= 1 * 11 * 35 / 4 * 10
= 9.625 cm²

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