Solve the quadratic equation in variable …

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Ans: abx²=(a+b)²(x-1) abx²=(a+b)²x-(a+b)² abx²-(a+b)²x+(a+b)²=0 here, a=ab , b=-(a+b)² , c=(a+b)² By quadratic formula x=-b +/- _/b²-4ac /2a = -[-(a+b)²]+/- _/ [-(a+b)²]²-4(ab)(a+b)²] / 2ab =(a+b)²+/- _/(a+b)⁴-4ab(a+b)² / 2ab = (a+b)²+/- _/(a+b)²[(a+b)²-4ab] / 2ab = (a+b)²+/- (a+b)_/a²+b²+2ab-4ab /2ab = (a+b)²+/-(a+b)_/a²+b²-2ab / 2ab = (a+b)²+/-(a+b)_/(a-b)² / 2ab =(a+b)²+/-(a+b)(a-b) / 2ab = a²+b²+2ab +/- a2-b² /2ab So, x=a²+b²+2ab+a²-b² / 2ab = 2a²+2ab /2ab = 2a(a+b) /2ab = a+b/b OR x=a²+b²+2ab-(a²-b²) / 2ab =a²+b²+2ab-a²+b² / 2ab = 2b²+2ab / 2ab =2b(b+a) /2ab = a+b/a Thus, the value of x= a+b/b , a+b/a

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