Deduce and expression for the electric …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Aniket Mahajan 7 months, 2 weeks ago
- 0 answers
Posted by Anterpreet Kaur 1 year, 3 months ago
- 0 answers
Posted by Khushbu Otti 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 5 years, 1 month ago
The magnitudes of the electric field due to the two charges +q and -q are given by,
The directions of E+q and E-q are as shown in the figure. The components normal to the dipole axis cancel away. The components along the dipole axis add up.
Therefore, Total electric field.
E = - (E+q + E-q) cosθ p [Negative sign shows that field is opposite to p]
At large distances (r>>a),this reduces to
1Thank You