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If cos(a+b)=0 show that sin(a-b)=?

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If cos(a+b)=0 show that sin(a-b)=?

Posted by Pradeep Yadav 5 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Gargi Nawghade 5 years, 3 months ago

Cos(a+b)=0 We know that, Cos 90 = 0 So, Cos(a+b) = Cos 90 => a+b = 90 => a = 90 - b Now, Sin(a-b) = Sin(90-b-b) = Sin(90-2b) = Cos 2b [ as Sin(90-x) = Cos x ] Thus, Sin(a-b) = Cos 2b

Rajesh Sharma 5 years, 3 months ago

cos (a+b) =0 => cos (a+b) = cos 90 => a+b = 90 => a = 90- b Now sin(a+b) = sin(90-b-b) = sin(90-2b) = cos 2b [as sin (90 - x) = cos x]

Yogita Ingle 5 years, 3 months ago

cos (a+b) =0

=> cos (a+b) = cos 90

=> a+b = 90

=> a = 90- b

Now

sin(a+b)

= sin(90-b-b)

= sin(90-2b)

= cos 2b [as sin (90 - x) = cos x]

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