Angle OAB=30°and angle OCB=57. FIND ANGLE …
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Posted by Supriyo Satyadarshi 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
Solution :-
Since, OC = OB (Radii of the same circle)
∴ ∠OBC = ∠OCB
⇒ ∠OBC = 57°
In △OBC, we have
∠OBC + ∠BOC + ∠OCB = 180°
57° + ∠BOC + 57° = 180°
⇒ ∠BOC = 66°
In △OAB,we have
∠OAB + ∠OBA + ∠AOB = 180° (Since, AO=OB ∴ ∠OAB = ∠OBA)
30° + 30° + ∠AOB = 180°
⇒ ∠AOB = 180° – 60°
⇒ ∠AOB = 120°
∠AOC = ∠AOB - ∠BOC
= 120° – 66° = 54°
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Yogita Ingle 5 years, 4 months ago
Since, OC = OB (Radii of the same circle)
∴ ∠OBC = ∠OCB
⇒ ∠OBC = 57°
In △OBC, we have
∠OBC + ∠BOC + ∠OCB = 180°
57° + ∠BOC + 57° = 180°
⇒ ∠BOC = 66°
In △OAB,we have
∠OAB + ∠OBA + ∠AOB = 180° (Since, AO=OB ∴ ∠OAB = ∠OBA)
30° + 30° + ∠AOB = 180°
⇒ ∠AOB = 180° – 60°
⇒ ∠AOB = 120°
∠ABC = 180 - ∠AOB - ∠OAB
= 180- ( 120° + 30)°
= 30°
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