The coordinates of the circumcenter of …

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Gaurav Seth 5 years, 3 months ago
from circumcentre distance of every vertex is same
let circumcentre point C
so AC=BC=CO
AC^2=BC^2=CO^2
by distance formula
AC^2 = BC^2
[(x-a)^2+(y-0)^2] = [(x-0)^2+(y-b)^2]
by solving
x^2+a^2 -2ax+ y^2 = x^2 +y^2+ b^2-2yb
2(by-ax)= b^2 -a^2 ---- (1)
NOW AC^2=OC^2
(x-0)^2 + (y-b)^2 = x^2 + y^2
by solving this equation y=b/2
put the value of y in (1) and we will get x=a/2
So answer is (a/2,b/2)
2Thank You