If the density of methanol is …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Divyanshi Goswami 5 years, 1 month ago
- 2 answers
Gaurav Seth 5 years, 1 month ago
Moles of methanol present in 2.5 L of 0.25 M solution
Moles of CH3OH = 2.5 * 0.25 = 0.625
Mass of CH3OH = 0.625 * 32 = 20 g
(∵ Molecular mass of CH3OH = 12 + 1 * 3 + 16 + 1 = 32)
0.793 * g of CH3OH is present in 1000 mL
20 g of CH3OH is present in
= mL
Related Questions
Posted by "Serai✨ Wallance" 1 year, 2 months ago
- 0 answers
Posted by Rihan Mehta 1 year, 2 months ago
- 0 answers
Posted by Naman Mehra 1 year, 2 months ago
- 0 answers
Posted by Shaila Bombe 1 year, 1 month ago
- 1 answers
Posted by Parneet Kaur 9 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Divyanshi Goswami 4 years, 7 months ago
0Thank You