If the density of methanol is …
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Posted by Divyanshi Goswami 3 years, 8 months ago
- 2 answers
Gaurav Seth 3 years, 8 months ago
Moles of methanol present in 2.5 L of 0.25 M solution
Moles of CH3OH = 2.5 * 0.25 = 0.625
Mass of CH3OH = 0.625 * 32 = 20 g
(∵ Molecular mass of CH3OH = 12 + 1 * 3 + 16 + 1 = 32)
0.793 * g of CH3OH is present in 1000 mL
20 g of CH3OH is present in
= mL
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Divyanshi Goswami 3 years, 2 months ago
0Thank You