Evaluate : Sin² 63° + Sin² …

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Posted by Tanishk Sharma 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
( sin ² 63° + sin ² 27° ) / ( cos ² 17° + cos ² 73° )
= { sin ² 63° + sin ² ( 90 - 63 ) ° } / { cos ² 17° + cos ² ( 90 - 17 ) ° }
= ( sin ² 63° + cos ² 63° ) / ( sin ² 17° + cos ² 17° )
= 1 / 1
= 1
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Kajal Sikarwar 5 years, 3 months ago
1Thank You