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Solve, exercise 5.1,Q.4,(xii)

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Solve, exercise 5.1,Q.4,(xii)

    • Posted by Vishakha Girl 5 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Vishakha Girl 5 years, 3 months ago

    Thanks

    0Thank You

    Gaurav Seth 5 years, 3 months ago

    (xii) √2, √8, √18, √32 …

    Here,

    a2 – a1 = √8-√2  = 2√2-√2 = √2

    a3 – a2 = √18-√8 = 3√2-2√2 = √2

    a4 – a3 = 4√2-3√2 = √2


    Since, an+1 – an or the common difference is same every time.

    Therefore, d = √2 and the given series forms a A.P.

    Hence, next three terms are;

    a5 = √32+√2 = 4√2+√2 = 5√2 = √50

    a6 = 5√2+√2 = 6√2 = √72

    a7 = 6√2+√2 = 7√2 = √98

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