Two vectors both equal in magnitude, …
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Yogita Ingle 5 years, 2 months ago
Let θθ be the angle between the two vectors A and B such that, |A| = |B|.
Therefore, R2=A2+B2+2ABcosθ
=>A2=A2+A2+2AAcosθ
[∵ |A| = |B| = |R|]
=>A2=2A2+2A2cosθ
=>cosθ=−1/2
=>θ=120∘
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