If the sum of n terms …

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Posted by Sunidhi Singh 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
Given that Sum to n terms of an AP is
3n² + n
Given common difference is 6,
If suppose a is the first term of A.P and 'd' is the
common difference, the Sum to n terms of an A.P is
given by Sn = (n/2)*[2a + (n - 1)d]
Given Sn = 3n² + n
If we substitute n = 1 , in Sn we get Sum to 1 tems of an A.P
which is equivalent to first term of A.P itself,
So, 1st term of A,P = S₁ = 3.1² + 1
= 3 + 1
= 4.
Hence, first term of an A.P is 4.
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Sunidhi Singh 5 years, 4 months ago
0Thank You