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Let the resistance be constant while the potential difference is halved. What will be the change in the current?

Posted by Aprita Pal 5 years, 4 months ago

CBSE > Class 10 > Science

2 answers

Gaurav Seth 5 years, 4 months ago

The amount of current flowing through the electrical component is reduced by half.

Explanation:

According to Ohm’s law

V = IR

where

V= potential difference

I= Current

R = Resistance

By modifying the equation

I=V/R ——- (i)

potential difference across the two ends of the component decreases to half

therefore, the new potential difference be Vʹ=V/2

Resistance remains constant across the electrical component

new current is drawn by the electrical component is Iʹ = Vʹ/R

= (V/2)/R {Substituting Vʹ=V/2 in the above equation}

= (1/2) (V/R)

= (1/2) I = I/2

Hence the amount of current flowing through the electrical component is reduced by half.

1Thank You

Avinash S 5 years, 4 months ago

Current will also get halved because current is directly proportional to potential difference

2Thank You

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Posted by Pandey Ji 5 months, 4 weeks ago

CBSE > Class 10 > Science