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Find the value of ‘k’ such …

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Find the value of ‘k’ such that the quadratic polynomial x2 - (k + 6) x + 2 (2k +1) has sum of the zeros is half of their product.

Posted by Ankur Kumar 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 3 months ago

Given quadratic polynomial,
x² - (k+6)x + 2(2k+1) = 0

By comparing it with ax²+bx+c = 0,we get
a = 1 , b = -(k+6) , c = 2(2k+1)

Sum of zeroes = -b/a
= -[-(k+6)]/1
= k+6

Product of zeroes = c/a
= 2(2k+1)/1
= 2(2k+1)

As per problem,
Sum of zeroes = ½ × product of zeroes
k+6 = ½ × 2(2k+1)
k+6 = 2k+1
2k-k = 6-1
k = 5

0Thank You

ANSWER

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