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A light bulb is rated at …

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A light bulb is rated at 100W for a 220v supply. Find a) the resistance of the bulb. b) The peak voltage of the source and c) the rms current through the bulb.

    • Posted by Suresh Sharma 5 years, 2 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Shubhanshu Tiwari 5 years, 2 months ago

    484ohm

    1Thank You

    Suresh Sharma 5 years, 2 months ago

    Pav = 100W, Vrms =220V a) R = V²rms➗ Pav = 484 b) V' = √2 ✖ 220 = 311V c) Irms = Pav ➗Vrms = 0.45

    2Thank You

    Suresh Sharma 5 years, 2 months ago

    Pav = 100W, Vrms =220V a) R = V²rms➗ Pav = 484 b) V' = √2 ✖ 220 = 311V c) Irms = Pav ➗Vrms = 0.45

    1Thank You

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