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Rationalise the denominator of 1/root5+root3

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Rationalise the denominator of 1/root5+root3
  • 2 answers

Sunisha Flower Decoretion 4 years, 2 months ago

1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer????

Shagun Nehra 4 years, 2 months ago

=1× root 5 - root 3/root 5 + root 3× root 5 - root 3 =Root 5 - root 3/ root 5 square - root 3 square =Root 5 - root 3 / 5 - 3 = Root 5 - root 3/2 Ans.
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