Five years hence the age of …
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Gaurav Seth 5 years, 3 months ago
Let us assume Jacob’s current age is x and his son’s current age is y.
Five years hence, Jacob’s age = x + 5 and his son’s age = y + 5
As per question;
x + 5 = 3(y + 5)
Or, x + 5 = 3y + 15
Or, x = 3y + 15 – 5 = 3y + 10
Five years ago, Jacob’s age = x – 5 and his son’s age = y – 5
As per question;
x – 5 = 7(y – 5)
Or, x – 5 = 7y – 35
Or, x = 7y – 35 + 5 = 7y – 30
Substituting the value of x from first equation in this equation, we get;
3y + 10 = 7y – 30
Or, 3y + 10 + 30 = 7y
Or, 7y – 3y = 40
Or, 4y = 40
Or, y = 10
Substituting the value of y in first equation, we get;
x = 3y + 10
Or, x = 3 x 10 + 10 = 40
Hence, Jacob’s age = 40 years and son’s age = 10 years
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