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Two charge particle are placed, at 2cm apart what is the minimum possible magnitude

    • Posted by Arif Jamal 5 years, 2 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    S P 5 years, 2 months ago

    F=kq1q2/r2 where both q1andq2= 1.6*10to power -19. Radius=2cm=2*10to power -2. Put all value F=9*10power9*1.6*10power-19*1.6*10power-19/2*10power-2*2*10power-2= 5.76*10power-25

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