Find a point on y axis …

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Gaurav Seth 5 years, 3 months ago
The point P(0,9) is equidistant from the points A(6,5) and B(-4,3).
Step-by-step explanation:
Let the point on y axis is P(0,y) which is equidistant from the points A(6,5) and B(-4,3). The distance between PA is equal to PB such that,
On squaring,
So, the point P(0,9) is equidistant from the points A(6,5) and B(-4,3).
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