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The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time ?

Posted by Himanshu Jagne 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

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CBSE > Class 10 > Mathematics