The sum of three no of …

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Gaurav Seth 5 years, 3 months ago
Let the numbers be a - d, a, a + d which are in AP.
(a - d) + (a) + (a + d) = 27 .........(1)
(a - d)(a)(a + d) = 405 ..........(2)
(1) => 3a = 27
a = 9
(2) => (a2 - d2)(a) = 405
[(9)2 - d2] (9) = 405
(81 - d2) (9) = 405
729 - 9d2 = 405
9d2 = 729 - 405
9d2 = 324
d2 = 36
d = 6
Now, substitute the values in the 1st equation.
(a-d) = 9 - 6 = 3
a = 9
(a+d) = 9 + 6 = 15
Hence the numbers are 3, 9 and 15.
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