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If a+b+c=0 find the value of (b+c)²/BC +(c+a)²/ca +(a+b)²/ab

Posted by Ridhima Sharma 4 years, 2 months ago

CBSE > Class 09 > Mathematics

4 answers

Sarita Panda 4 years, 2 months ago

Ans is 3

0Thank You

Gaurav Seth 4 years, 2 months ago

Given : a + b + c = 0

To Find :

From the given equation, we can find out :

a + b + c = 0

b + c = - a
c + a = - b
a + b = - c

Putting these equations in the above equation, we get

→

• {Identity : (a + b + c)³ = a³ + b³ + c³ - 3abc }

→ Given that a + b + c = 0, then

(0)³ = a³ + b³ + c³ - 3abc

a³ + b³ + c³ = 3abc

Putting this in above equation, we get

→

→ 3

0Thank You

Suzanne Smitha 4 years, 2 months ago

a+b+c=0 1. b+c=-a 2. a+b=-c 3. c+a=-b -a^3/bc + -b^3/ca + -c^3/ab =-(a^3+b^3+c^3)/abc =3abc/abc =3

0Thank You

Hanshika (Honey) 4 years, 2 months ago

A+b+c=0 1. b+c=-a 2. a+b=-c 3. c+a=-b = (-a)^3/bc + (-b)^3/ca + (-c)^3/ab =-(a^3+b^3+c^3)/abc =-3abc/abc =-3

0Thank You

ANSWER

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CBSE > Class 09 > Mathematics