A triangular side walls of a …

The perimeter of a triangle is equal to the sum of its three sides it is denoted by 2S. 2s=(a+b+c) s=(a+b+c)/2 Here ,s is called semi perimeter of a triangle. The formula given by Heron about the area of a triangle is known as Heron's formula. According to this formula area of a triangle= √s (s-a) (s-b) (s-c) Where a, b and c are three sides of a triangle and s is a semi perimeter. This formula can be used for any triangle to calculate its area and it is very useful when it is not possible to find the height of the triangle easily . Heron's formula is generally used for calculating area ofSolution: Let the sides of the triangle are a=122 m, b=22 m & c= 120 m. Semi Perimeter of the ∆,s = (a+b+c) /2 s=(122 + 22 + 120) / 2 s= 264/2= 132m Using heron’s formula, Area of the wall = √s (s-a) (s-b) (s-c) = √132(132 – 122) (132 – 22) (132 – 120) = √132 × 10 × 110 × 12 =√11×12×10×11×10×12 =√11×11×12×12×10×10 = 11×12×10 = 1320m² Given, earning on 1m² per year= ₹5000 Earning on 1320 m² per year=1320×5000= ₹6600000 Now, earning in 1320 m² in 12 months= ₹6600000 earning in 3 months = ₹ 6600000 ×3/12 = ₹ 1650000 Hence, the rent paid by the company for 3 months is ₹ 1650000.