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H.C.F. of 128 and 68 is …

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H.C.F. of 128 and 68 is expresible in the form of 128m-15 ×68 .Find the value of m.Also find L.C.M of 128 and 68 using prime factorisation method.

Posted by Rahul Soni 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Manju Angadi 5 years, 3 months ago

L. C. M of128 & 68 >128=2×2×2×2×2×2 >682=2×2×17 :-L. C. M. is 2176 L. C. M×H. C. F= products of two numbers 2176×128m-15×68=128×68 >2176×128m-15×68=8704 >128m-15×68=8704÷2176 >128m-15=4÷68 >128m=0.05882352941+15 >128m=15.05882352941 >m=15.05882352941÷128 Ans:-m=0.11764705882

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CBSE > Class 10 > Mathematics