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The roots of the equation a²b²x²-(4b⁴-3a⁴)x-12a²b²=0

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The roots of the equation a²b²x²-(4b⁴-3a⁴)x-12a²b²=0

Posted by Arnav Kumar 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Prajwal Mehra 5 years, 3 months ago

A²b²x² - (4b⁴ - 3a⁴)x - 12a²b² = 0 ⇒a²b²x² - 4b⁴x + 3a⁴x - 12a²b² = 0 ⇒b²x(a²x - 4b²) + 3a²(a²x - 4b²) = 0 ⇒(b²x + 3a²)(a²x - 4b²) = 0 ⇒x = 4b²/a², -3a²/b² now, using quadratic formula , x = {(4b⁴ - 3b⁴) ± √{(4b⁴ -3a⁴)²+48(a²b²)²}}/2a²b² = {(4b⁴ - 3a⁴) ± √{(4b⁴ + 3a⁴)²}}/2a²b² [ use formula, (x-y)²+4xy=(x+y)²] = {4b⁴ - 3a⁴ ± (4b⁴ + 3a⁴)}/2a²b² = 4b²/a², -3a²/b² LE BHAI

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CBSE > Class 10 > Mathematics