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a+b+c=9 and ab+bc+ca=23then a3+b3+c3-3abc=

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a+b+c=9 and ab+bc+ca=23then a3+b3+c3-3abc=

Posted by Thanushree Bhat 4 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Suzanne Smitha 4 years, 2 months ago

It is given that, 1. a+b+c=9 2.ab+bc+ca=23 Do the square of equation( 1) we get. (a+b+c)^2 = 9^2. a^2+b^2+c^2 +2(ab+bc+ca)=81. a^2+b^2+c^2+ 2(23)=81 a^2+b^2+c^2+46 =81 3. a^2+b+c=81_46=35 Now, a^3+b^3+c^3_ 3abc = (a+b+c)[a^2+b^2+c^2_ (ab+bc+ ca)] =9[35_ 23] =9[12] =108 Hope it helps you.

1Thank You

Bangtan Army Forever 4 years, 2 months ago

I think the correct answer is 108.hope it help you

1Thank You

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CBSE > Class 09 > Mathematics