No products in the cart.

Simplify by rationalising the denominator 10/5 …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Simplify by rationalising the denominator 10/5 sq root -3 sq root 5 with method
  • 1 answers

Hulash Dhruw 4 years, 3 months ago

For rationalising the denominator of any number 1/√a-b , we multiply it by √a+b/√a+b. =10/√5-3× √5+3/√5+3 =10×√5+3/5+(3)² =10√5+3/14
http://mycbseguide.com/examin8/

Related Questions

3√2×4√2×12√32
  • 0 answers
X³-12x²+39x-28
  • 0 answers
Ch-1 introduction
  • 0 answers
2x+5y
  • 0 answers
What is 38747484±393884747
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App