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If alfha and beta are the zeros of the polynomials p(x)= X square - px - (p +c ) ,then find the value of ( alpha+1) * (beta+1)

Posted by Bhavya Gupta 5 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Hk Honey 5 years, 3 months ago

Hey

1Thank You

Bhavya Gupta 5 years, 4 months ago

It's wrong i.e answer is wrong answer is qx²+px+1

1Thank You

Prakriti Dubey 5 years, 4 months ago

c = - 1 Step-by-step explanation: x² - p ( x + 1 ) + c ⇒ x² - p x - p + c ⇒ x² - p x + ( c - p ) Comparing with ax² + bx + c, we get : a = 1 b = - p c = c - p . Given : ( α + 1 )( β + 1 ) = 0 ⇒ αβ + α + β + 1 = 0 Note that, sum of roots = - b/a α + β = - b / a But b = - p a = 1 So α + β = - ( - p ) / 1 = p Product of roots = αβ = c / a ⇒ αβ = ( c - p ) Hence write this as : αβ + α + β + 1 = 0 ⇒ c - p + p + 1 = 0 ⇒ c + 1 = 0 ⇒ c = -1

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CBSE > Class 10 > Mathematics