Kx+2y=5 3x-4y=10

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Veshu Pathak 5 years, 4 months ago
- 1 answers
Related Questions
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Hari Anand 5 months, 1 week ago
- 0 answers
Posted by Kanika . 6 days, 4 hours ago
- 1 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 1 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Gaurav Seth 5 years, 4 months ago
The given system of equations:
kx + 2y = 5
⇒ kx + 2y - 5 = 0 ….(i)
3x - 4y = 10
⇒3x - 4y - 10 = 0 …(ii)
These equations are of the forms:
Thus for all real values of k other than −3/2 , the given system of equations will have a unique solution.
(ii) For the given system of equations to have no solutions, we must have:
1Thank You