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By what % will the illumination of the lamp decrease if the current drops by 20% ?

Posted by Shreya Kumari 5 years, 5 months ago

CBSE > Class 10 > Science

1 answers

Gaurav Seth 5 years, 5 months ago

H = I^2Rt

if the current drops by 20%

so, new current (I') = 0.8I

Hence, H' = (0.8I)^2Rt

H' = 0.64H

Hence, the brightness would decrease by H-(0.64H)/100 = 36%

2Thank You

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CBSE > Class 10 > Science