Let the first no. be 'a' Therefore the terms of the AP are a , a+d ,a+2d ,a+3d. So, a+(a+d)+(a+2d)+(a+3d)=50 4a+6d=50 2a + 3d = 25.......i now we know that the 4th term is 4times the first term. Therefore, 4a = a+3d 3a = 3d a = d......ii Substituting ii in i we get 2a+3a=25 a = 5 Thus the AP is 5 , 10 , 15 , 20 ....

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Arun Arun 5 years, 4 months ago

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