An object of 4 cm height …

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Posted by Riyana D'Cunha 5 years, 5 months ago
- 2 answers
Yogita Ingle 5 years, 5 months ago
Using the lens formula; -1/u+1/v=1/f
rearranging, 1/v=1/18-1/27=1/54
hence 1/v=1/54.
To get the position of the image, V, find the reciprocal of 1/54.
Hence, v=54cm.
To obtain the size and nature of image,
use magnifcation formula; hi=V/u*h=54/-27*4=-8.0cm.
Therefore, size of image is 8cm.
Nature=virtual image.
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Riyana D'Cunha 5 years, 5 months ago
0Thank You