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Find the ratio in which the …

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Find the ratio in which the line segment joining the points (-3,10)and (6,-8)is divided by (-1,6)

    • Posted by Choti Inani 5 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    ? Pranali.A.P ? 5 years, 4 months ago

    Here x₁ = -3, y₁ = 10, x₂ = 6, y₂ = -8  ......          [m(6) + n (-3)]/(m+n) , [m (-8) + n (10)]/(m+n) = (-1,6) .......         (6m - 3n)/(m+n), (-8m+10n)/(m+n) = (-1,6) .......  equating the coefficients of x and y.......     (6m-3n)/(m+n) = -1    .......   (-8m+10n)/(m+n) = 6...........        6m -  3n = -1 (m+n)............      6m - 3n = -1 (m+n)..........       6m-3n=-m-n..........       6m+m=-n+3n.........        7m=2n.. .........         m/n= 2/7.........         m:n = 2:7.......... So the point (-1,6) is dividing the line segment in the ratio 2:7.

    0Thank You

    Gaurav Seth 5 years, 4 months ago

    Let P(-1, 6) divides the line segment joining the points A(-3, 10) and B(6, -8) in the ratio K : 1.
    Then the co-ordinates of P are given by

    Here, we have
    x1 = -3, y1 = 10
    x2 = 6, y2 = -8
    and    m1 = K, m2 = 1
    So, the co-ordinates of P are



    But the co-ordinates of P are given as P(-1, 6)


    Hence, required ratio = 2 : 7.

    0Thank You

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