Find the zeroes of quadratic Polyno …
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Gaurav Seth 5 years, 4 months ago
-√(2/3),√(2/3) are zeroes of the given polynomial
Explanation:
Given Quadratic polynomial p(x) = 3x²-2
i) To find the zeroes of p(x),
we must take p(x)=0
3x²-2 = 0
=> 3x² = 2
=> x² = 2/3
=> x = ±√(2/3)
Verification:
Let m,n are two zeroes of the polyomial,
m = -√(2/√3)and n = √(2/3)
Compare p(x) with ax²+bx+c , we get
a = 3 , b = 0 , c=-2
i) sum of the zeroes =
= -√(2/3)+√(2/3)
= 0
=
ii) Product of the zeros
= [-√(2/3)][√(2/3)]
= -2/3
=
0Thank You