Express the trigonometric ratios sinA, secA …
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Posted by Vicky Arora 5 years, 1 month ago
- 2 answers
Yogita Ingle 5 years, 1 month ago
[ i ] sinA in terms of cotA :
sinA = 1 / cosecA
We know that: cosec²A = 1 + cot²A
sinA = 1 / √1 + cot²A
[ ii ] secA in terms of cotA :
We know that: 1 + tan²A = sec²A
secA = 1 + tan²A
secA = 1 + 1 / cot²A
secA = √(cot²A + 1 ) /cotA
[ iii ] tanA in terms of cotA :
tanA = 1 / cotA
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Omkar Meher 5 years, 1 month ago
0Thank You