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Sin(b+c)/2cosA/2+cos(b+c)/2Sina/2

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Sin(b+c)/2*cosA/2+cos(b+c)/2*Sina/2

Posted by Shibi Vs 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Ranjan 5 years, 4 months ago

We knoe that A+B+C=180 B+C=180-A (B+C)/2=(180-A)/2 (B+C)/2=90-A/2 Cos(B+C)/2=Cos(90-A/2) Cos(B+C)/2=Sin A/2 Or, Sin(B+C)/2=Sin(90-A/2) Sin(B+C)/2=Cos A/2 Now, According to question Sin(b+c)/2 * cos A/2 +cos(b+c)/2 *sin A/2 Cos A/2 *cos A/2 + sinA/2 *sin A/2 Cos^2 A/2+sin^ A/2 1 is ur answer

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