if the zeros of the polynomial …

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Gaurav Seth 5 years, 4 months ago
Given that cubic polynomial,
x³-3x²+x+1
then,
(a-b)+a+(a+b)=-b/a
3a=-(-3)/1
3a=3
a=3/3
a=1
Again,
(a-b)*a*(a+b)=-d/a
a(a²-b²)=-1/1
1(1²-b²=-1
1-b²=-1
-b²=-1-1
-b²=-2
b±2
b=±√2
that
a=1
b=√2
1Thank You