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. Find the least number of square tiles required to pave the ceiling of a room 15m 17 cm long and 9m 2cm broad

    • Posted by R D Passwan 5 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 5 years, 4 months ago

    It is given that: 

    Length of a tile = 15m 17m = 1517cm [∵ 1m = 100cm] 

    Breadth of a tile = 9m 2m = 902cm 

    ∴ Side of each square tile = HCF (1517, 902) 

    Prime factorization: 

    1517 = 37 × 41 

    902 = 22 × 41 

    ∴ HCF = product of smallest power of each common prime factor in the numbers = 41 

    ∴ Required number of tiles = Area of ceiling/Area of one tile = 1517 x 902/ 41 x 41 = 37 x 22 = 814

    1Thank You

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