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bx+ay-ab(a+b)=0 b^2x+a^2y-2a^2b^2

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bx+ay-ab(a+b)=0 b^2x+a^2y-2a^2b^2
  • 1 answers

Gaurav Seth 5 years, 4 months ago

The system of linear equations with variables x and y are given to be

⇒ b³x - a³y = a²b²(a + b) .......... (1)

⇒ b³x - a³y = a³b² + a²b³ ........... (2)

And, the other equation is

b²x - a²y = 2a²b² ............ (3)

⇒ b³x - a²by = 2a²b³ ............ (4)

Now, solving equations (2) and (4) we get,

a²by - a³y = a³b² + a²b³ - 2a²b³ = a³b² - a²b³

⇒ a²(b - a)y = a²b²(a - b)

⇒ y = - b²

Now, from equation (3) we get

b²x - (-b²)a² = 2a²b²

⇒ b²x = a²b²

⇒ x = a²

Therefore, the solution for x is x = a². (Answer)

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