4x²-4ax+(a²-b²) 4x²-4ax+(a+b)(a-b)=0 m²-n² =(m+n)(m-n) Splitting the middle term, we get => 4x² -2(a+b)x-2(a-b)x +(a+b)(a-b)=0 => 2x[2x-(a+b)]-(a-b)[2x-(a+b)]=0 => [2x-(a+b)][2x-(a-b)]=0 => 2x-(a+b)=0 Or 2x-(a-b)=0 => 2x = a+b Or 2x = a-b Then x=a+b/2,x=a-b/2

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Lucifer?? Morningstar?? 5 years, 4 months ago

4x²-2(a+b)x-2(a-b)x+(a²-b²) => 2x{x-(a+b)}-2(a-b){x-(a+b)} => (2x-2a+2b)(x-a-b) => x=a--b or a+b

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