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Find the value of under root …

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Find the value of under root 6+ root 6 + root 6 + ...

Posted by Liv 5 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Gaurav Seth 5 years, 4 months ago

1Thank You

Gaurav Seth 5 years, 4 months ago

Given : x = √6 + √6 + √6 +... ---(i)

Then,
x = √6 + x --- From Eqn. (i)

On squaring both sides,

⇒ x² = 6 + x

⇒ x² - x - 6 = 0

⇒ x² - 3x + 2x - 6 = 0

⇒ x(x-3) + 2(x-3) = 0

⇒ x = 3 Or x = -2

But x is a natural number.
∴ x = 3

1Thank You

Liv 5 years, 4 months ago

Can you write it step-by-step! By the way sis not bro.

0Thank You

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CBSE > Class 10 > Mathematics